(6x+8)^(1/2)=3x

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Solution for (6x+8)^(1/2)=3x equation:



(6x+8)^(1/2)=3x
We move all terms to the left:
(6x+8)^(1/2)-(3x)=0
We add all the numbers together, and all the variables
(6x+8)^(+1/2)-3x=0
We add all the numbers together, and all the variables
-3x+(6x+8)^(+1/2)=0
We multiply all the terms by the denominator
-3x*2)+(6x+1+8)^(=0
We add all the numbers together, and all the variables
-3x*2)+(6x+9)^(=0
We add all the numbers together, and all the variables
-3x*2)+(6x=0
Wy multiply elements
-6x^2=0
a = -6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-6)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-12}=0$

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